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x^2/3=10.5
We move all terms to the left:
x^2/3-(10.5)=0
We add all the numbers together, and all the variables
x^2/3-10.5=0
We multiply all the terms by the denominator
x^2-(10.5)*3=0
We add all the numbers together, and all the variables
x^2-31.5=0
a = 1; b = 0; c = -31.5;
Δ = b2-4ac
Δ = 02-4·1·(-31.5)
Δ = 126
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{126}=\sqrt{9*14}=\sqrt{9}*\sqrt{14}=3\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{14}}{2*1}=\frac{0-3\sqrt{14}}{2} =-\frac{3\sqrt{14}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{14}}{2*1}=\frac{0+3\sqrt{14}}{2} =\frac{3\sqrt{14}}{2} $
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